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Sample Power Data Analysis Examples Two Independent Proportions Power Analysis

Introduction

Power analysis is the name given to the process for determining the sample
size for a research study.  The technical definition of power is the
probability of detecting a "true" effect when it exists.  Many students
think that there is a simple formula for determining sample size for every
research situation.  However, the reality is that there are many research
situations that are so complex that they almost defy rational power analysis. In
most cases, power analysis involves making simplifying assumptions that make the
problem tractable and running the analyses numerous times with different
variations to cover all of the contingencies.

In this unit we will try to illustrate how to do a power analysis for a test
of two independent proportions, i.e., the response variable has two levels and
the predictor variable also has two levels.  Instead of analyzing these data
using a test of independent proportions, we could compute a chi-square statistic
in a 2×2 contingency table or run a simple logistic regression analysis.  These
three analyses yield the same results and would require the same sample sizes to
test effects.

Description of the experiment

It is known that a certain type of skin lesion will develop into cancer in 30%
of patients if left untreated.  There is a drug on the market that will
reduce the probability of cancer developing by 10%.  A pharmaceutical
company is developing a new drug to treat skin lesions but it will only be
worthwhile to do so if the new drug is at least 5% better than the existing drug. 
The pharmaceutical company plans to do a study with patients randomly assigned
to two groups, the control (untreated) group and the treatment group.  The
company wants to know how many subjects will be needed to test a difference in
proportions of .15 with a power of .8 at alpha equal to .05.

We will make use of a Sample Power ‘2×2 for independent samples (Chi-squared
or Fischer’s exact test)’ procedure, under the ‘Proportions’ tab in the
Procedures catalog.

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To proceed, we will need to provide the following information:

  • the expected proportion
    of cancer in the untreated group (p1 = .3)
  • the expected proportion of cancer
    in the treated group (p2 = .3 – .15 = .15)
  • the alpha level (alpha = .05, the
    default in Sample Power)
  • the required level of power (power = .8)
  • (accessible via the ‘Find N for any power’ button).

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    This is all well and good, but a two-sided test doesn’t make much sense in
    this situation.  We want to test for a drug that reduces the probability of
    cancer not for one that increases the probability.  In this case we should be
    using one-tail test and we do this by using the clicking "Tails=2" in the lower
    left-hand corner and selecting the one-tailed option.

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    This is better.  The result indicates that we need to use 95 subjects in each
    group to find a change in probability of .15 for a power of .8 when alpha equals
    .05

    Because we believe that we know a lot about the incidence of cancer in
    the untreated group, we would like to make the control group half as large as the
    treatment group. By clicking on the ‘N Per Group’ column header, we open an
    options window allowing us to adjust the ratio between sample sizes. 
    By setting ‘Link Sample Size in two groups’ on with cases in a ratio of 1 to
    2, we ensure that the treatment group will be twice the control.

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    As you can see, we will need more subjects overall than for equal sized
    groups but we can have a much smaller untreated group.

    In the end, the company has decided to use 75 patients in the control group
    and 150 in the treatment group.  Let’s see what the power is.

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    With this unbalanced design we have an estimated power of .82 which the
    company deems acceptable.

    For more information on power analysis, please visit our

    Introduction to Power Analysis

    seminar.